Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:34Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
det| 9 4 ; 1 10 | = 86
158K
d/dn [n^4] = 4n^3
∑_{k=1}^{n} k = n(n+1)/2
376K
∑_{k=1}^{n} k = n(n+1)/2
139K
det| 2 4 ; 4 3 | = -10
344K
det| 8 2 ; 7 9 | = 58
91K