Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:35Z
∑_{k=1}^{n} k = n(n+1)/2
det| 2 7 ; 7 3 | = -43
269K
12ω² + 6ω + 7 = 0
det| 5 6 ; 4 6 | = 6
131K
det| 9 4 ; 1 10 | = 86
158K
d/dn [n^4] = 4n^3
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
376K
∫₀^∞ e^(-α²) dα = √π / 2
344K