Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:35Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
det| 6 4 ; 4 7 | = 26
240K
∫₀^∞ e^(-φ²) dφ = √π / 2
376K
det| 9 1 ; 1 10 | = 89
∫₀^∞ e^(-φ²) dφ = √π / 2
139K
det| 9 7 ; 3 10 | = 69
344K
det| 1 6 ; 5 2 | = -28
∑_{k=1}^{n} k = n(n+1)/2
91K
det| 10 7 ; 3 11 | = 89
399K