Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:57Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
269K
12ω² + 6ω + 7 = 0
det| 9 7 ; 3 10 | = 69
158K
d/dn [n^4] = 4n^3
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
240K
det| 9 1 ; 1 10 | = 89
det| 7 4 ; 4 8 | = 40
139K
det| 1 6 ; 5 2 | = -28
∑_{k=1}^{n} k = n(n+1)/2
201K