Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 00:36Z
∇ × E = −∂B/∂t
det| 11 2 ; 1 12 | = 130
det| 9 7 ; 3 10 | = 69
131K
∑_{k=1}^{n} k = n(n+1)/2
det| 3 6 ; 0 4 | = 12
240K
det| 1 1 ; 1 2 | = 1
10ψ² + 2ψ + 3 = 0
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
295K
CH₄ + 2O₂ → CO₂ + 2H₂O
4t² + 3t + 3 = 0
11ψ² + 4ψ + 6 = 0