Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:58Z
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
269K
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
det| 10 7 ; 3 11 | = 89
240K
∑_{k=1}^{n} k = n(n+1)/2
376K
det| 9 1 ; 1 10 | = 89
∑_{k=1}^{n} k = n(n+1)/2
344K