Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:40Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
det| 11 5 ; 0 12 | = 132
131K
d/dn [n^4] = 4n^3
∑_{k=1}^{n} k = n(n+1)/2
240K
det| 7 4 ; 4 8 | = 40
376K
det| 9 1 ; 1 10 | = 89
det| 5 6 ; 4 6 | = 6
344K