Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:52Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
269K
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
∫₀^∞ e^(-y²) dy = √π / 2
240K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
139K
∑_{k=1}^{n} k = n(n+1)/2
344K