Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:58Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
∑_{k=1}^{n} k = n(n+1)/2
240K
det| 6 6 ; 2 7 | = 30
376K
det| 9 1 ; 1 10 | = 89
det| 9 4 ; 1 10 | = 86
344K
det| 5 3 ; 2 6 | = 24
295K