Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:58Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
det| 12 1 ; 5 13 | = 151
131K
det| 3 3 ; 4 4 | = 0
158K
d/dn [n^4] = 4n^3
∑_{k=1}^{n} k = n(n+1)/2
240K
∑_{k=1}^{n} k = n(n+1)/2
376K
det| 9 1 ; 1 10 | = 89
det| 7 4 ; 4 8 | = 40
139K
det| 1 6 ; 5 2 | = -28
∑_{k=1}^{n} k = n(n+1)/2
201K
det| 8 2 ; 7 9 | = 58
295K