Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:54Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
det| 3 6 ; 0 4 | = 12
131K
det| 9 7 ; 3 10 | = 69
158K
d/dn [n^4] = 4n^3
det| 9 4 ; 1 10 | = 86
376K
det| 9 1 ; 1 10 | = 89
∑_{k=1}^{n} k = n(n+1)/2
344K
det| 1 6 ; 5 2 | = -28
∑_{k=1}^{n} k = n(n+1)/2
201K