Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 18:44Z
9n² + 9n + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
269K
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
158K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\frac{11}{8} \sum_{i=1}^{n} i^{2}
376K
ΔS ≥ 0
det| 7 4 ; 4 8 | = 40
139K
det| 4 6 ; 0 5 | = 20
344K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
295K
\frac{12}{7} \sum_{i=1}^{n} i^{2}
399K