Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 22:13Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
36K
det| 7 4 ; 4 8 | = 40
269K
11β² + 9β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
131K
ω = 2πf
Fe₂O₃ + 3CO → 2Fe + 3CO₂
376K
∫₀^∞ e^(-α²) dα = √π / 2
139K