Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-20 02:05Z
3r² + 3r + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
322K
∫₀^∞ e^(-φ²) dφ = √π / 2
235K
6ω² + 6ω + 6 = 0
∫₀^∞ e^(-y²) dy = √π / 2
det| 5 9 ; 7 6 | = -33
179K
∫₀^∞ e^(-ψ²) dψ = √π / 2
det| 5 3 ; 2 6 | = 24
42K
det| 1 7 ; 2 2 | = -12