Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:18Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
269K
12ω² + 6ω + 7 = 0
∫₀^∞ e^(-t²) dt = √π / 2
131K
det| 4 8 ; 3 5 | = -4
158K
d/dn [n^4] = 4n^3
det| 7 4 ; 4 8 | = 40
376K
det| 9 1 ; 1 10 | = 89
det| 5 6 ; 4 6 | = 6
139K
det| 1 6 ; 5 2 | = -28
∑_{k=1}^{n} k = n(n+1)/2
91K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
201K