Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-20 16:02Z
2ψ² + 9ψ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
193K
∇²t = 0
10t² + 9t + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
362K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
405K
det| 9 4 ; 1 10 | = 86
42K