Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 00:24Z
∇ × E = −∂B/∂t
det| 11 2 ; 1 12 | = 130
∑_{k=1}^{n} k = n(n+1)/2
131K
∑_{k=1}^{n} k = n(n+1)/2
det| 1 1 ; 1 2 | = 1
det| 12 1 ; 5 13 | = 151
139K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
344K
10ψ² + 2ψ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
201K
N₂ + 3H₂ ⇌ 2NH₃
4t² + 3t + 3 = 0