Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:38Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
36K
∑_{k=1}^{n} k = n(n+1)/2
269K
12ω² + 6ω + 7 = 0
det| 7 4 ; 4 8 | = 40
131K
d/dn [n^4] = 4n^3
det| 8 5 ; 3 9 | = 57
139K
∑_{k=1}^{n} k = n(n+1)/2
344K