Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:29Z
∑_{k=1}^{n} k = n(n+1)/2
det| 8 6 ; 6 9 | = 36
36K
det| 11 5 ; 0 12 | = 132
269K
12ω² + 6ω + 7 = 0
det| 4 4 ; 5 5 | = 0
131K
d/dn [n^4] = 4n^3
det| 9 1 ; 1 10 | = 89
∑_{k=1}^{n} k = n(n+1)/2
91K
∑_{k=1}^{n} k = n(n+1)/2
201K