Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:10Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-z²) dz = √π / 2
269K
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
det| 9 1 ; 1 10 | = 89
Fe₂O₃ + 3CO → 2Fe + 3CO₂
201K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
295K
∑_{k=1}^{n} k = n(n+1)/2
399K