Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:29Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
36K
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
det| 2 7 ; 7 3 | = -43
376K
det| 9 1 ; 1 10 | = 89
∫₀^∞ e^(-n²) dn = √π / 2
139K
det| 1 6 ; 5 2 | = -28
Fe₂O₃ + 3CO → 2Fe + 3CO₂
295K
∑_{k=1}^{n} k = n(n+1)/2
399K