Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:41Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
269K
12ω² + 6ω + 7 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
131K
d/dn [n^4] = 4n^3
∑_{k=1}^{n} k = n(n+1)/2
240K
det| 7 4 ; 4 8 | = 40
376K
det| 9 1 ; 1 10 | = 89
∑_{k=1}^{n} k = n(n+1)/2
139K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
344K
det| 1 6 ; 5 2 | = -28
∑_{k=1}^{n} k = n(n+1)/2
91K