Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 05:59Z
\frac{11}{2} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
36K
∑_{k=1}^{n} k = n(n+1)/2
4ψ² + 5ψ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
ω = 2πf
\binom{n}{k} = \frac{n!}{k!(n-k)!}
295K