Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:28Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
36K
12ω² + 6ω + 7 = 0
det| 2 2 ; 4 3 | = -2
131K
∫₀^∞ e^(-ω²) dω = √π / 2
158K
d/dn [n^4] = 4n^3
det| 7 4 ; 4 8 | = 40
240K
∑_{k=1}^{n} k = n(n+1)/2
376K
det| 9 1 ; 1 10 | = 89
∑_{k=1}^{n} k = n(n+1)/2
399K