Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:52Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
36K
∑_{k=1}^{n} k = n(n+1)/2
269K
12ω² + 6ω + 7 = 0
det| 8 2 ; 7 9 | = 58
158K
d/dn [n^4] = 4n^3
det| 9 4 ; 1 10 | = 86
376K
∑_{k=1}^{n} k = n(n+1)/2
344K