Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:54Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
36K
12ω² + 6ω + 7 = 0
det| 4 4 ; 5 5 | = 0
131K
d/dn [n^4] = 4n^3
det| 9 4 ; 1 10 | = 86
376K
det| 9 1 ; 1 10 | = 89
CH₄ + 2O₂ → CO₂ + 2H₂O
139K
∑_{k=1}^{n} k = n(n+1)/2
344K
det| 1 6 ; 5 2 | = -28
∑_{k=1}^{n} k = n(n+1)/2
91K
ω = 2πf