Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:27Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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12ω² + 6ω + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
158K
d/dn [n^4] = 4n^3
det| 9 4 ; 1 10 | = 86
240K
∫₀^∞ e^(-α²) dα = √π / 2
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