Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:28Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
36K
det| 5 6 ; 1 6 | = 24
269K
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
det| 9 4 ; 1 10 | = 86
376K
det| 9 1 ; 1 10 | = 89
∫₀^∞ e^(-φ²) dφ = √π / 2
139K
det| 10 7 ; 3 11 | = 89
344K
∑_{k=1}^{n} k = n(n+1)/2
91K