Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:56Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
158K
d/dn [n^4] = 4n^3
CH₄ + 2O₂ → CO₂ + 2H₂O
240K
det| 9 1 ; 1 10 | = 89
det| 7 4 ; 4 8 | = 40
139K
det| 3 3 ; 4 4 | = 0
344K
det| 1 6 ; 5 2 | = -28
det| 4 7 ; 2 5 | = 6
201K
ω = 2πf