Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:55Z
∑_{k=1}^{n} k = n(n+1)/2
det| 8 6 ; 6 9 | = 36
36K
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
det| 9 1 ; 1 10 | = 89
det| 11 9 ; 5 12 | = 87
344K
∑_{k=1}^{n} k = n(n+1)/2
201K
det| 6 6 ; 2 7 | = 30
295K