Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:43Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
det| 9 4 ; 1 10 | = 86
131K
det| 8 5 ; 3 9 | = 57
158K
d/dn [n^4] = 4n^3
det| 11 2 ; 5 12 | = 122
240K
det| 2 6 ; 0 3 | = 6
139K
∑_{k=1}^{n} k = n(n+1)/2
91K