Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-20 16:47Z
2ψ² + 9ψ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
445K
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
322K
10t² + 9t + 7 = 0
det| 7 4 ; 4 8 | = 40
212K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
405K
CH₄ + 2O₂ → CO₂ + 2H₂O
442K