Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:43Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
36K
det| 5 6 ; 1 6 | = 24
269K
12ω² + 6ω + 7 = 0
det| 7 4 ; 4 8 | = 40
131K
d/dz [z^11] = 11z^10
158K
d/dn [n^4] = 4n^3
det| 9 1 ; 1 10 | = 89
det| 8 2 ; 7 9 | = 58
139K
det| 5 3 ; 2 6 | = 24
344K
∑_{k=1}^{n} k = n(n+1)/2
91K