Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:39Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
131K
d/dn [n^4] = 4n^3
∑_{k=1}^{n} k = n(n+1)/2
240K
det| 9 1 ; 1 10 | = 89
det| 9 9 ; 5 10 | = 45
139K
det| 1 6 ; 5 2 | = -28
det| 12 9 ; 5 13 | = 111
91K
∑_{k=1}^{n} k = n(n+1)/2
201K
det| 9 4 ; 1 10 | = 86
295K