Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:25Z
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
36K
det| 11 9 ; 0 12 | = 132
269K
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
376K
det| 9 4 ; 1 10 | = 86
344K
∫₀^∞ e^(-t²) dt = √π / 2
201K
∑_{k=1}^{n} k = n(n+1)/2
399K