Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-20 02:14Z
3r² + 3r + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
d/dz [z^11] = 11z^10
235K
6ω² + 6ω + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
212K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
362K
∫₀^∞ e^(-y²) dy = √π / 2
det| 7 4 ; 4 8 | = 40
179K
∑_{k=1}^{n} k = n(n+1)/2
405K