Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-21 08:05Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
436K
det| 5 5 ; 1 6 | = 25
∑_{k=1}^{n} k = n(n+1)/2
355K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
228K
∑_{k=1}^{n} k = n(n+1)/2
28K