Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 00:48Z
∇ × E = −∂B/∂t
det| 11 2 ; 1 12 | = 130
det| 11 5 ; 0 12 | = 132
131K
∑_{k=1}^{n} k = n(n+1)/2
det| 1 1 ; 1 2 | = 1
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
139K
∑_{k=1}^{n} k = n(n+1)/2
344K
10ψ² + 2ψ + 3 = 0
N₂ + 3H₂ ⇌ 2NH₃
CH₄ + 2O₂ → CO₂ + 2H₂O
4t² + 3t + 3 = 0
11ψ² + 4ψ + 6 = 0