Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:52Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
36K
det| 2 7 ; 7 3 | = -43
269K
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
det| 9 4 ; 1 10 | = 86
376K
CH₄ + 2O₂ → CO₂ + 2H₂O
139K
∑_{k=1}^{n} k = n(n+1)/2
344K