Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:30Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
det| 7 4 ; 4 8 | = 40
376K
det| 9 1 ; 1 10 | = 89
det| 5 6 ; 1 6 | = 24
344K
det| 1 6 ; 5 2 | = -28
∑_{k=1}^{n} k = n(n+1)/2
91K
det| 11 9 ; 0 12 | = 132
201K
det| 2 2 ; 4 3 | = -2
399K