Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:48Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
131K
∑_{k=1}^{n} k = n(n+1)/2
158K
d/dn [n^4] = 4n^3
det| 2 2 ; 4 3 | = -2
240K
det| 9 4 ; 1 10 | = 86
376K
det| 9 1 ; 1 10 | = 89
det| 2 4 ; 4 3 | = -10
344K
det| 1 6 ; 5 2 | = -28
e^{i\pi} + 1 = 0
ω = 2πf
ΔS ≥ 0