Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:58Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 7 ; 2 5 | = 6
269K
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
det| 9 4 ; 1 10 | = 86
240K
∑_{k=1}^{n} k = n(n+1)/2
376K
det| 9 1 ; 1 10 | = 89
det| 1 6 ; 5 2 | = -28
det| 2 7 ; 7 3 | = -43
91K