Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:53Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
det| 4 2 ; 3 5 | = 14
158K
d/dn [n^4] = 4n^3
∑_{k=1}^{n} k = n(n+1)/2
240K
∫₀^∞ e^(-x²) dx = √π / 2
139K
∫₀^∞ e^(-φ²) dφ = √π / 2
295K