Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:56Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
131K
∫₀^∞ e^(-n²) dn = √π / 2
158K
d/dn [n^4] = 4n^3
det| 7 4 ; 4 8 | = 40
376K
det| 9 1 ; 1 10 | = 89
det| 9 7 ; 3 10 | = 69
139K
det| 1 6 ; 5 2 | = -28
CH₄ + 2O₂ → CO₂ + 2H₂O
91K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
295K
ΔS ≥ 0
4r² + 4r + 6 = 0
9r² + 1r + 4 = 0