Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:59Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
269K
12ω² + 6ω + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
158K
d/dn [n^4] = 4n^3
det| 2 4 ; 4 3 | = -10
240K
∑_{k=1}^{n} k = n(n+1)/2
376K
CH₄ + 2O₂ → CO₂ + 2H₂O
344K