Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-20 02:12Z
3r² + 3r + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
445K
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
322K
6ω² + 6ω + 6 = 0
∫₀^∞ e^(-y²) dy = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
405K
det| 9 4 ; 1 10 | = 86
42K