Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 00:46Z
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
36K
∫₀^∞ e^(-t²) dt = √π / 2
269K
det| 11 2 ; 1 12 | = 130
∑_{k=1}^{n} k = n(n+1)/2
det| 1 1 ; 1 2 | = 1
det| 7 4 ; 4 8 | = 40
344K
10ψ² + 2ψ + 3 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
201K