Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:52Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
269K
12ω² + 6ω + 7 = 0
det| 1 4 ; 2 2 | = -6
158K
d/dn [n^4] = 4n^3
det| 9 1 ; 1 10 | = 89
∫₀^∞ e^(-α²) dα = √π / 2
139K
det| 1 5 ; 1 2 | = -3
344K
det| 1 6 ; 5 2 | = -28
∑_{k=1}^{n} k = n(n+1)/2
91K
ω = 2πf
det| 4 7 ; 2 5 | = 6
399K
4r² + 4r + 6 = 0