Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:47Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
269K
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
det| 7 7 ; 4 8 | = 28
240K
det| 9 4 ; 1 10 | = 86
376K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
139K
∑_{k=1}^{n} k = n(n+1)/2
344K