Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:54Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
269K
12ω² + 6ω + 7 = 0
det| 4 6 ; 4 5 | = -4
131K
det| 9 4 ; 1 10 | = 86
158K
d/dn [n^4] = 4n^3
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
376K
∑_{k=1}^{n} k = n(n+1)/2
139K
det| 2 4 ; 4 3 | = -10
344K
det| 4 8 ; 3 5 | = -4
91K